3x/x^2-25=15/x^2-25-4/x+5

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Solution for 3x/x^2-25=15/x^2-25-4/x+5 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x)/(x^2)-25 = 15/(x^2)-(4/x)-25+5 // - 15/(x^2)-(4/x)-25+5

(3*x)/(x^2)+4/x-(15/(x^2))-25-5+25 = 0

(3*x)/(x^2)+4/x-15*x^-2-25-5+25 = 0

7*x^-1-15*x^-2-5 = 0

t_1 = x^-1

7*t_1^1-15*t_1^2-5 = 0

7*t_1-15*t_1^2-5 = 0

DELTA = 7^2-(-15*(-5)*4)

DELTA = -251

DELTA < 0

x belongs to the empty set

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